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T20: W Brace

Example T20: W Brace with Reduced cross-section

This example shows the computation of the factored tension resistance of a W shape used as a tension member in a lateral brace in a building such as that shown in the following photo. There are 4 braces shown. Note that the upper left brace has the flange tips removed from the W-shape (to ensure ductility under seismic forces). We will compute the strength of a brace similar to that shown in the photo.

from Designer import DesignNotes, SST, Part, show
%figure "DSC6443-small.jpg"

Load and Setup the Library Modules

import pint                  # setup to use the module for computing with units
ureg = pint.UnitRegistry()
mm = ureg['mm']
inch = ureg['inch']
kN = ureg['kN']
MPa = ureg['MPa']
ureg.default_format = '~P'
notes = DesignNotes('Tr',units=kN)      # initial the note/record keeping object
RECORD = notes.record     # useful abbreviations
CHECK = notes.check
USEVARS = notes.usevars

Problem Statement

Compute the factored tension resistance, $T_r$, of the following assembly. Steel is G40.21 350W and bolts are 3/4" ASTM A325 in 22mm punched holes.

%figure "brace1.svg"
image/svg+xml W250x67 L102x76x13 PL8x190x310 C L sym. Elevation 40 102 40 40 75 40 40 75 75 75 75 75 30

Note that 40mm is cut from each flange tip of the W250x67.

Angles

%figure "angle.svg"
image/svg+xml 40 3@75=225 80 3@75=225 40 g2 b d g1 d+b-t g1+g2-t "flattened" 1 1 2 2
class Bolts(Part):
    "Bolts"
    grade = 'ASTM A325'
    size = '3/4"'
    d = (3/4*inch).to(mm)
    Fu = 825*MPa
    Ab = 3.14159*d**2/4.
    n = 4                    # number of bolts per end
    s = 75.*mm                  # bolt spacing
    threads_intercepted = True

Bolts.show()
Ab                  = 285   mm²
d                   = 19.05 mm
Fu                  = 825   MPa
grade               = ASTM A325 
n                   = 4     
s                   = 75    mm
size                = 3/4"  
threads_intercepted = True  
class Angles(Part):
    "Angles"
    grade = 'CSA G40.21 350W'
    Fy = 350*MPa
    Fu = 450*MPa
    d,b,t,Ag,size = SST.section('L102x76x13','D,B,T,A,Dsg')
    d = d*mm
    b = b*mm
    t = t*mm
    Ag = Ag*mm*mm
    ha = (22 + 2)*mm  # hole allowance  - punched holes
    g1 = 65*mm        # gauge, longer leg
    g2 = 45*mm        # gauge, shorter leg
    s = 80*mm         # dist between innermost holes on each end

Angles.show()
Ag    = 2100 mm²
b     = 76.2 mm
d     = 102  mm
Fu    = 450  MPa
Fy    = 350  MPa
g1    = 65   mm
g2    = 45   mm
grade = CSA G40.21 350W 
ha    = 24   mm
s     = 80   mm
size  = L102x76x13 
t     = 12.7 mm

Check Details (TO BE DONE!)

  • Bolt spacings, edge distances
  • Fit within flanges (need gusset thickness)
CHECK(False,'Bolting and fitting details have not been checked.')
    Bolting and fitting details have not been checked.?  NG! *****
      ()

Net Section Fracture:

phiu = 0.75

with USEVARS(('d,b,t,ha,g1,g2,Fu,s',Angles),
             ('n',Bolts),
             locals='wg,wn1,g,wn2,wn,An,Ane', globals='phiu',
             record='Tr',label='Net section fracture, 4 angles',
             ):
    # gross width = "flattened" width of angle:
    wg = d + b - t

    # failure path 1-1: 1 hole
    wn1 = wg - 1*ha

    # failure path 2-2: 2 holes
    g = g1 + g2 - t
    wn2 = wg - 2*ha + s**2/(4*g)

    wn = min(wn1,wn2)

    An = wn*t
    Ane = 0.8*An if n >= 4 else 0.6*An   # S16-14: 12.3.3.2 (b) (i) - connected 1 leg n lines of bolts
    
    Tr = 4. * phiu*Ane*Fu    # S16-14: 13.2 a) iii)
d     = 102       mm
b     = 76.2      mm
t     = 12.7      mm
ha    = 24        mm
g1    = 65        mm
g2    = 45        mm
Fu    = 450       MPa
s     = 80        mm
n     = 4         
wg    = 165.5     mm
wn1   = 141.5     mm
g     = 97.3      mm
wn2   = 133.9     mm
wn    = 133.9     mm
An    = 1701      mm²
Ane   = 1361      mm²
Tr    = 1.837e+06 MPa·mm²
phiu  = 0.75      
    Net section fracture, 4 angles: Tr = 1837 kN

Gross Section Yield:

phi = 0.9
with USEVARS(('Ag,Fy',Angles),
            label='Gross section yield, 4 angles'):
    Tr = 4. * phi*Ag*Fy    # S16-14: 13.2 a) i)
Ag    = 2100      mm²
Fy    = 350       MPa
Tr    = 2.646e+06 MPa·mm²
    Gross section yield, 4 angles: Tr = 2646 kN

Block Shear

with USEVARS(('t,d,b,g1,g2,ha,Fy,Fu',Angles),
             ('n,s',Bolts),
             locals='Agv,An,Ut',
             label='Block shear, 4 angles'):
    Agv = (40*mm + (n-1)*s)*t
    An = (min(d-g1,b-g2) - ha/2.)*t
    Ut = 0.3     # SUPER conservative
    Tr = 4. * phiu*(Ut*An*Fu + 0.6*Agv*(Fy+Fu)/2.)
t     = 12.7      mm
d     = 102       mm
b     = 76.2      mm
g1    = 65        mm
g2    = 45        mm
ha    = 24        mm
Fy    = 350       MPa
Fu    = 450       MPa
n     = 4         
s     = 75        mm
Agv   = 3366      mm²
An    = 243.8     mm²
Ut    = 0.3       
Tr    = 2.522e+06 MPa·mm²
    Block shear, 4 angles: Tr = 2522 kN

Tr for W Shape

%figure "w.svg"
image/svg+xml W250x67 PL8x190x310 40 190 1 1 arearemoved
class WShape(Part):
    "WShape"
    grade = 'ASTM A992'
    Fy = 345*MPa
    Fu = 450*MPa
    Ag,b,d,t,w,size = SST.section('W250x67',properties='A,B,D,T,W,Dsg')
    Ag = Ag*mm*mm
    b = b*mm
    d = d*mm
    t = t*mm
    w = w*mm
    wp = 190*mm          # width of web reinforcing PL
    tp = 8*mm            # thickness of web reinforcing PL
    wc = 40*mm           # width cut from flange tips

Net section fracture

# Path 1-1: net = gross  +  plates  -  holes
with USEVARS(('ha',Angles),
             ('Ag,tp,wp,w,Fu',WShape), 
             locals='An,Ane',
             label='Net section fracture, W shape'):
    An = Ag  +  2*tp*wp   -  2*ha*(w+tp+tp)
    Ane = 0.85*An    # S16-14: 12.3.3.2 (c) (i)
    phiu = 0.75
    Tr = phiu*Ane*Fu
ha    = 24        mm
Ag    = 8550      mm²
tp    = 8         mm
wp    = 190       mm
w     = 8.9       mm
Fu    = 450       MPa
An    = 10390     mm²
Ane   = 8836      mm²
Tr    = 2.982e+06 MPa·mm²
    Net section fracture, W shape: Tr = 2982 kN

Gross section yield

with USEVARS(('Ag,wc,t,Fy',WShape),
             locals='Agr',
             label='Gross section yield, W shape'):
    Agr = Ag - 4*wc*t   # reduced area due to flange cuts
    phi = 0.9
    Tr = phi*Fy*Agr     # S16-14: 13.2 a) i)
Ag    = 8550      mm²
wc    = 40        mm
t     = 15.7      mm
Fy    = 345       MPa
Agr   = 6038      mm²
Tr    = 1.875e+06 MPa·mm²
    Gross section yield, W shape: Tr = 1875 kN

Block Shear

with USEVARS(('ha,g2',Angles),
             ('w,tp,Fy,Fu',WShape),
             ('n,s',Bolts),
             locals='Agv,An,Ut',
             label='Block shear, W shape'):
    T = w + tp + tp          # thickness of web + reinforcing plates
    Agv = 2*(40*mm + (n-1)*s)*T
    An = (g2 + g2 + 25*mm - ha)*T   # estimate 25mm spacing between angles (gusset thickness)
    Ut = 1.0
    phiu = 0.75
    Tr = phiu*(Ut*An*Fu + 0.6*Agv*(Fy+Fu)/2.)       # S16-14: 13.11
ha    = 24        mm
g2    = 45        mm
w     = 8.9       mm
tp    = 8         mm
Fy    = 345       MPa
Fu    = 450       MPa
n     = 4         
s     = 75        mm
Agv   = 13200     mm²
An    = 2266      mm²
Ut    = 1         
Tr    = 3.125e+06 MPa·mm²
    Block shear, W shape: Tr = 3125 kN

Tearout

with USEVARS(('w,tp,Fy,Fu',WShape),
             ('n,s',Bolts),
             locals='An,Ahv,Ut',  label='Tearout, W shape'):
    Agv = 4*(40*mm + (n-1)*s)*T
    An = 0*mm*mm
    Ut = 1.0
    phiu = 0.75
    Tr = phiu*(Ut*An*Fu + 0.6*Agv*(Fy+Fu)/2.)       # S16-14: 13.11
w     = 8.9       mm
tp    = 8         mm
Fy    = 345       MPa
Fu    = 450       MPa
n     = 4         
s     = 75        mm
An    = 0         mm²
Ahv   = None      
Ut    = 1         
Tr    = 4.721e+06 MPa·mm²
    Tearout, W shape: Tr = 4721 kN

Bolt Shear

with USEVARS(('n,s,Ab,Fu,threads_intercepted',Bolts),
             locals='m,L',    label='Bolt Shear'):
    phib = 0.8
    m = 2
    Tr = 0.6*phib*n*m*Ab*Fu * 2   # S16 13.12.1.2.b)
    L = (n-1)*s   # length of connection
    if L >= 760*mm:
        Tr = Tr * (0.5/0.6)
    if threads_intercepted:
        Tr = Tr * 0.7
n                   = 4         
s                   = 75        mm
Ab                  = 285       mm²
Fu                  = 825       MPa
threads_intercepted = True      
m                   = 2         
L                   = 225       mm
Tr                  = 1.264e+06 MPa·mm²
    Bolt Shear: Tr = 1264 kN    <<<--- GOVERNS

Bolt Bearing

with USEVARS(('t,Fu',Angles),
             ('n,d',Bolts),
             record='Br', label='Bolt Bearing (on 4 angles)'):
    phibr = 0.8
    Br = 3*phibr*n*t*d*Fu * 4
t     = 12.7      mm
Fu    = 450       MPa
n     = 4         
d     = 19.05     mm
Br    = 4.181e+06 MPa·mm²
    Bolt Bearing (on 4 angles): Tr = 4181 kN
with USEVARS(('w,tp,Fu',WShape),
             ('n,d',Bolts),
             locals='t',     record='Br', label='Bolt Bearing (on web of W)'):
    t = w+tp+tp
    Br = 3*phibr*(n*2)*t*d*Fu
w     = 8.9       mm
tp    = 8         mm
Fu    = 450       MPa
n     = 4         
d     = 19.05     mm
t     = 24.9      mm
Br    = 4.098e+06 MPa·mm²
    Bolt Bearing (on web of W): Tr = 4098 kN

Summary

notes.summary()
Summary of DesignNotes for Tr
=============================

Checks:
-------
    Bolting and fitting details have not been checked.?   NG! *****
      ()

Values of Tr:
-------------
    Net section fracture, 4 angles: Tr = 1840 kN
    Gross section yield, 4 angles:  Tr = 2650 kN
    Block shear, 4 angles:          Tr = 2520 kN
    Net section fracture, W shape:  Tr = 2980 kN
    Gross section yield, W shape:   Tr = 1870 kN
    Block shear, W shape:           Tr = 3130 kN
    Tearout, W shape:               Tr = 4720 kN
    Bolt Shear:                     Tr = 1260 kN    <<<--- GOVERNS
    Bolt Bearing (on 4 angles):     Tr = 4180 kN
    Bolt Bearing (on web of W):     Tr = 4100 kN

    Governing Value:
    ----------------
       Tr = 1260 kN

To do:

  • check bolt detailing
  • check fit of angles between flanges
  • bolts, bearing - gusset and web
  • weld, reinforcing plates to web
  • thickness of gusset plate. Bolts allow 100-45-45 = 10mm. too little.

Notes

  • Note that gross section yield of the W should govern, but it does not, by a large margin.
    • Obviously, more bolts are required, or detail them so that threads are not intercepted (risky for installation considerations).
    • Another thing to try would be slightly larger angles. Perhaps L127x76x13 (which would not require any additional space between flanges).
    • Or could shave a few more millimeters from flange tips.
    • Of course, all this has to be compared with factored applied loads.