T20: W Brace
Example T20: W Brace with Reduced cross-section
This example shows the computation of the factored tension resistance of a W shape used as a tension member in a lateral brace in a building such as that shown in the following photo. There are 4 braces shown. Note that the upper left brace has the flange tips removed from the W-shape (to ensure ductility under seismic forces). We will compute the strength of a brace similar to that shown in the photo.
Note that 40mm is cut from each flange tip of the W250x67.
class Angles(Part):
"Angles"
grade = 'CSA G40.21 350W'
Fy = 350*MPa
Fu = 450*MPa
d,b,t,Ag,size = SST.section('L102x76x13','D,B,T,A,Dsg')
d = d*mm
b = b*mm
t = t*mm
Ag = Ag*mm*mm
ha = (22 + 2)*mm # hole allowance - punched holes
g1 = 65*mm # gauge, longer leg
g2 = 45*mm # gauge, shorter leg
s = 80*mm # dist between innermost holes on each end
Angles.show()
phiu = 0.75
with USEVARS(('d,b,t,ha,g1,g2,Fu,s',Angles),
('n',Bolts),
locals='wg,wn1,g,wn2,wn,An,Ane', globals='phiu',
record='Tr',label='Net section fracture, 4 angles',
):
# gross width = "flattened" width of angle:
wg = d + b - t
# failure path 1-1: 1 hole
wn1 = wg - 1*ha
# failure path 2-2: 2 holes
g = g1 + g2 - t
wn2 = wg - 2*ha + s**2/(4*g)
wn = min(wn1,wn2)
An = wn*t
Ane = 0.8*An if n >= 4 else 0.6*An # S16-14: 12.3.3.2 (b) (i) - connected 1 leg n lines of bolts
Tr = 4. * phiu*Ane*Fu # S16-14: 13.2 a) iii)
class WShape(Part):
"WShape"
grade = 'ASTM A992'
Fy = 345*MPa
Fu = 450*MPa
Ag,b,d,t,w,size = SST.section('W250x67',properties='A,B,D,T,W,Dsg')
Ag = Ag*mm*mm
b = b*mm
d = d*mm
t = t*mm
w = w*mm
wp = 190*mm # width of web reinforcing PL
tp = 8*mm # thickness of web reinforcing PL
wc = 40*mm # width cut from flange tips
with USEVARS(('ha,g2',Angles),
('w,tp,Fy,Fu',WShape),
('n,s',Bolts),
locals='Agv,An,Ut',
label='Block shear, W shape'):
T = w + tp + tp # thickness of web + reinforcing plates
Agv = 2*(40*mm + (n-1)*s)*T
An = (g2 + g2 + 25*mm - ha)*T # estimate 25mm spacing between angles (gusset thickness)
Ut = 1.0
phiu = 0.75
Tr = phiu*(Ut*An*Fu + 0.6*Agv*(Fy+Fu)/2.) # S16-14: 13.11
Notes
- Note that gross section yield of the W should govern, but it does not, by a large margin.
- Obviously, more bolts are required, or detail them so that threads are not intercepted (risky for installation considerations).
- Another thing to try would be slightly larger angles. Perhaps L127x76x13 (which would not require any additional space between flanges).
- Or could shave a few more millimeters from flange tips.
- Of course, all this has to be compared with factored applied loads.